Issue 19028 - Italian dictionary always included
Summary: Italian dictionary always included
Status: CLOSED IRREPRODUCIBLE
Alias: None
Product: Build Tools
Classification: Code
Component: code (show other issues)
Version: OOo 1.1 RC3
Hardware: PC Windows XP
: P3 Trivial (vote)
Target Milestone: ---
Assignee: Martin Hollmichel
QA Contact: issues@tools
URL:
Keywords:
Depends on:
Blocks:
 
Reported: 2003-09-03 20:52 UTC by simonbr
Modified: 2004-02-17 09:03 UTC (History)
1 user (show)

See Also:
Issue Type: DEFECT
Latest Confirmation in: ---
Developer Difficulty: ---

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Description simonbr 2003-09-03 20:52:18 UTC 
The Italian dictionary is included in the installation set, regardless the 
environment variable DICT_ITIT is unset.
Comment 1 khendricks 2003-09-04 18:53:34 UTC 
Hi, 
 
I can't see how this can happen.  The dictionary/it_IT/makefile.mk explicitly tests 
DICT_ITIT and will not do anything unless it is set in some way: 
 
Taken right from dictionary/it_IT/makefile.mk 
 
.IF "$(DIC_ITIT)"!="" 
 
all_target: $(MISC)$/$(TARGET).don 
 
DIC2BIN= \ 
        it_IT.aff \ 
        it_IT.dic \ 
        hyph_it_IT.dic \ 
        README_it_IT.txt 
 
 
$(MISC)$/$(TARGET).don : 
        +$(COPY) $(foreach,i,$(DIC2BIN) $i) $(BIN) 
        @echo DICT it IT it_IT >>$(BIN)$/dictionary.lst 
        @echo HYPH it IT hyph_it_IT >>$(BIN)$/dictionary.lst 
        @touch $@ 
 
.ENDIF 
 
 
The only way it could still be appearing is if you one time had DICT_ITIT set and it 
was generated and a clean rebuild (removal of the dictionary output tree) was not 
done. 
 
Either that or the unsetenv DICT_ITIT was not done in *.Set file? 
 
So I am not sure how this is happening? 
 
Kevin
Comment 2 simonbr 2003-09-04 22:07:50 UTC 
Right.
I cleanly rebuilt dictionaries and the Italian dictionary was not 
included anymore in the build. 
Sorry for the inconvenience...
Comment 3 Martin Hollmichel 2004-02-17 09:01:21 UTC 
verified.
Comment 4 Martin Hollmichel 2004-02-17 09:03:36 UTC 
close issue.